X^2-18=17x

Solution for X^2-18=17x equation:

X^2-18=17X

We move all terms to the left:

X^2-18-(17X)=0

a = 1; b = -17; c = -18;
Δ = b2-4ac
Δ = -172-4·1·(-18)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-19}{2*1}=\frac{-2}{2}
=-1
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+19}{2*1}=\frac{36}{2}
=18
$